小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com2023-2024学年下学期期末模拟考试（安徽专用）七年级数学一、选择题（本大题共10小题，每小题4分，共40分．在每小题给出的四个选项中，只有一个选项是符合题目要求的）12345678910ACCADADCCD二、填空题（本大题共4小题，每小题4分，共16分）11.12.13.14.三、（本大题共2小题，每小题5分，满分10分）15．【答案】(1)0(2)或【分析】本题主要考查了实数的运算，求平方根的方法解方程：（1）先计算算术平方根和立方根，再计算加减法即可；（2）根据求平方根的方法解方程即可．【详解】（1）解：；··············································2分（2）解： ，∴，∴或，∴或．·············································5分16．【答案】，整数解为，，0，1【分析】本题主要考查了解一元一次不等组，不等式组的整数解，解题的关键是熟练掌握解不等式组的基本步骤，能根据不等式的解集得出不等式组的解集．先分别求出两个不等式的解集，再求出不等式组的解集，最后求出整数解，即可解答．小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com【详解】解：解不等式①，得，·············································1分解不等式②，得·············································2分∴原不等式组的解集为·············································4分∴原不等式组的整数解为，，0，1．·············································5分四、（本大题共2小题，每小题6分，满分12分）17．【答案】令，结果为6【分析】根据分式的运算法则化简，取合适的字母值代入计算；【详解】解：·············································4分令，原式．·············································6分【点睛】本题考查分式的化简求值，掌握分式的运算法则是解题的关键．18．【答案】(1)，，(2)见解析(3)【分析】本题考查了作图﹣平移变换，作图时要先找到图形的关键点，分别把这几个关键点按照平移的方向和距离确定对应点后，再顺次连接对应点即可得到平移后的图形．（1）根据点的坐标表示方法写出点，，的坐标；（2）根据（1）描点连线即可；（3）根据点的坐标平移方法即可求解．【详解】（1），，；·············································3分（2）如图，三角形即为所作；小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com·············································4分（3）由题意可知，故答案为：．·············································6分五、（本大题共2小题，每小题8分，满分16分）19．【答案】(1)，见解析(2)【分析】此题考查了平行线的性质和判定定理，熟练掌握各定理是解题的关键：（1）由推出，得到，进而推出；（2）根据角平分线的性质得到，及，求出，再利用平行线的性质求出的度数．【详解】（1），理由如下： ，∴，即， ，∴，∴·············································3分（2） 平分，，∴，·············································5分∴，∴·············································6分 ，小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com∴，∴··············...