小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com2024学年第一学期丽水五校高中发展共同体期中联考高一年级物理学科参考答案命题1：庆元中学吴锋联系电话：13735940160命题2：松阳一中王潜龙联系电话：13757095366命题3：青田中学林燕平联系电话：13567649994一．选择题二．非选择题19.（1）0.05（2）BD（3）0.4751.2520.（1）3.70（3.68，3.69，3.70，3.71，3.72均给分）（2）B（3）CD（4）丙21.（1）根据匀变速直线运动公式，可得·············································（2分）解得a=8m/s2·························································································（1分）（2）根据匀变速直线运动公式，可得v=at·······················································（2分）解得v=24m/s························································································（1分）（3）由匀变速直线运动平均速度公式可得：······································（2分）解得··················································································（1分）22.（1）对结点O受力分析可知·················································（2分）联立解得x=0.32m····························································（1分）（2）对结点O受力分析可知·························································（1分）1234567891011121314CDCBABCCABDAAA15161718ADABBCCD小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com对A受力分析可知·································································（1分）联立解得mA=5kg·························································································（1分）（3）再次对A受力分析可知············································（2分）解得f=8N，方向沿斜面向下···········································································（2分）23.（1）由匀变速规律可知······················································（3分）又a1=2a2解得a1=1.6m/s2，a2=0.8m/s2··························································（1分）（2）由匀变速规律可知解得v1=vm=0.8m/s，································（1分）所以························································································（1分）又感应距离l=v人t························································································（1分）解得l=0.75m·······························································································（1分）（3）搬运物体到感应区后，门先匀加速移动0.2m，若搬运物体成功，门至少还要匀减速移动的距离为···········································································（1分）由可得门做匀减速运动用时或（舍去）则开门用时················································································（1分）可得所以物体的移动速度不能超过·····························（1分）